- By Beverly Fusfield - Provides detailed, worked-out solutions to the odd-numbered end-of-section and Chapter Review exercises and solutions to all of the Practice Tests and Cumulative Review problems-16r2 +5000 = 1000 =agt;-16r2 =-4000 =agt; t2 = 250 =agt; t = Ap7250 t = Ap15.8 Reject the negative solution. ... ar - as = fa - fa a(r2-52) = Z?(5-r) a(r2 - s2) = -b(r - s) r2-s2 b b = r + s = r-s a a To find r ac s , first divide both sides of ar2 + br + c = 0 by a. ... Now use the results from the a a first part of the problem and substitute -(r + s) for a .

Title | : | Student Solutions Manual for College Algebra |

Author | : | J. S. Ratti, Marcus S. McWaters |

Publisher | : | Addison-Wesley - 2007-06-01 |

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