Instead of plotting the fraction defective in a sample of size n, one plots the number of defectives, and the control chart ... 1 Solution. Here p = tj: 7 5 5 200 + 200 + + 200 1 150 TM x 77^7 = 0025 30 200 np =200x0.025 = 5 The control-chart anbsp;...

Title | : | Probability, Queueing Theory and Reliability Engineering |

Author | : | Laxmi Publications, Laxmi Publications Haribaskaran, G. |

Publisher | : | Laxmi Publications - 2005 |

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