student solutions manual Charles Henry Edwards, David E. Penney .0.02 = 4?- = -^Trh2 -dh dt aquot; 25 dt * So at the time in question, dh 1 25 1 dt aquot; 50 81tt aquot; aquot; 162tt a#39; approximately -0.001965 ft/sec, about -0.0236 ... Let x denote the distance between the ship and A, y the distance between the ship and B, h the perpendicular distance from the position of the ship to the line AB, ... y-dt + (12-6 aquot; u]~aragt; so du 1 , dx dy alt;, dt aquot; 12.6 lX dt aquot; y dt J* From the data given, du/dt is approximately 16.0857.

Title | : | Calculus and analytic geometry |

Author | : | Charles Henry Edwards, David E. Penney |

Publisher | : | - 1988 |

Continue