Alan Tucker. Boxes 2, 3, 4, 5 must each have at least one x. So put one x in each of these boxes and then count the ways to distribute ... I Example 6 I-Iow many integer solutions are there to the equation x, + x2+ x, + x4= 12, with x, agt;0. ... The respective answers are C(12a 1, 4a1)= 165 and C((12a2a2a4)+4a 1, 4a1)= 35.
|Publisher||:||John Wiley & Sons - 1980|